{"id":17766,"date":"2024-03-02T00:16:45","date_gmt":"2024-03-02T00:16:45","guid":{"rendered":"https:\/\/soicau3109.minhngocxoso.com\/bat-mi-3-cach-bat-tong-dac-biet-khi-choi-lo-de-mien-bac\/"},"modified":"2024-03-02T00:16:45","modified_gmt":"2024-03-02T00:16:45","slug":"bat-mi-3-cach-bat-tong-dac-biet-khi-choi-lo-de-mien-bac","status":"publish","type":"post","link":"https:\/\/cauchuan3cang.com\/bat-mi-3-cach-bat-tong-dac-biet-khi-choi-lo-de-mien-bac\/","title":{"rendered":"B\u1eadt m\u00ed 3 c\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t khi ch\u01a1i l\u00f4 \u0111\u1ec1 mi\u1ec1n B\u1eafc"},"content":{"rendered":"
\n
\n
\n

B\u1eadt m\u00ed 3 c\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t khi ch\u01a1i l\u00f4 \u0111\u1ec1 mi\u1ec1n B\u1eafc<\/h1>\n<\/header>\n<\/div>\n
\n
\"B\u1eadt<\/div>\n

Khi ch\u01a1i l\u00f4 \u0111\u1ec1 mi\u1ec1n B\u1eafc th\u00ec <\/span><\/i>c\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t<\/i><\/b>, l\u00e0 m\u1ed9t trong nh\u1eefng ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u \u0111\u01b0\u1ee3c c\u00e1c tay ch\u01a1i chuy\u00ean nghi\u1ec7p y\u00eau th\u00edch. B\u1edfi ph\u01b0\u01a1ng ph\u00e1p n\u00e0y tuy \u0111\u01a1n gi\u1ea3n nh\u01b0ng l\u1ea1i kh\u00e1 hi\u1ec7u qu\u1ea3; k\u1ebft h\u1ee3p kinh nghi\u1ec7m v\u00e0 t\u01b0 duy nhanh nh\u1ea1y c\u1ee7a ng\u01b0\u1eddi ch\u01a1i n\u00ean th\u01b0\u1eddng d\u1ec5 tr\u00fang. B\u00e0i vi\u1ebft h\u00f4m nay; s\u1ebd gi\u1edbi thi\u1ec7u \u0111\u1ebfn c\u00e1c b\u1ea1n 3 c\u00e1ch b\u1eaft c\u00e1c t\u1ed5ng trong l\u00f4 \u0111\u1ec1 gi\u00fap t\u0103ng t\u1ec9 l\u1ec7 th\u1eafng l\u00ean cao nh\u1ea5t. H\u00e3y tham kh\u1ea3o ngay nh\u00e9!<\/span><\/i><\/p>\n

C\u00e1ch b\u1eaft s\u1ed1 \u0111\u1ec1 d\u1ef1a theo quy lu\u1eadt c\u1ed9ng Pascal<\/b><\/h2>\n

Quy lu\u1eadt c\u1ed9ng Pascal \u0111\u01b0\u1ee3c \u00e1p d\u1ee5ng trong <\/span>c\u00e1ch b\u1eaft s\u1ed1 \u0111\u1ec1 hi\u1ec7u qu\u1ea3 <\/span>nh\u01b0 sau:<\/span><\/p>\n

    \n
  • Ng\u01b0\u1eddi ch\u01a1i ti\u1ebfn h\u00e0nh d\u00f9ng 5 s\u1ed1 gi\u1ea3i nh\u1ea5t v\u00e0 5 s\u1ed1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t gh\u00e9p v\u1edbi nhau. Ti\u1ebfp theo c\u1ed9ng 3 s\u1ed1 li\u1ec1n nhau li\u00ean ti\u1ebfp theo quy lu\u1eadt Pascal.<\/span><\/li>\n
  •  Tr\u01b0\u1eddng h\u1ee3p t\u1ed5ng c\u1ed9ng l\u1ea1i l\u1edbn h\u01a1n 10 s\u1ebd l\u1ea5y con s\u1ed1 h\u00e0ng \u0111\u01a1n v\u1ecb v\u00e0 c\u1ee9 th\u1ebf c\u1ed9ng khi ch\u1ec9 c\u00f2n 2 con s\u1ed1, r\u1ed3i d\u00f9ng s\u1ed1 \u0111\u00f3 \u0111\u1ec3 \u0111\u00e1nh l\u00f4 \u0111\u1ec1 ng\u00e0y h\u00f4m sau. <\/span><\/li>\n
  • C\u00e1c c\u1ea7u s\u1ed1 tr\u00ean \u0111\u01b0\u1ee3c nu\u00f4i trong v\u00f2ng 3 ng\u00e0y.<\/span><\/li>\n<\/ul>\n

    V\u00ed d\u1ee5 ng\u00e0y 29\/7\/2024, gi\u1ea3i \u0111\u1eb7c bi\u1ec7t l\u00e0 20464 v\u00e0 gi\u1ea3i nh\u1ea5t l\u00e0 10454. Ti\u1ebfn h\u00e0nh gh\u00e9p s\u1ed1 l\u1ea1i ch\u00fang ta \u0111\u01b0\u1ee3c 2046410454, sau \u0111\u00f3 c\u1ed9ng theo quy lu\u1eadt Pascal \u0111\u01b0\u1ee3c ti\u1ebfp c\u00e1c chu\u1ed7i s\u1ed1 l\u00e0: 2046410454 \u2013 240051499 \u2013 64056538 \u2013 0451181 \u2013 496299 \u2013 35818 \u2013 8399 \u2013 128 \u2013 30. Nh\u01b0 v\u1eady, 3 ng\u00e0y sau t\u1ee9c ng\u00e0y 1\/8\/2024 l\u00f4 v\u1ec1 30.<\/span><\/p>\n

    \"B\u1eadt<\/p>\n

    B\u1eaft t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t b\u1eb1ng c\u00e1ch t\u00ednh l\u00f4<\/b><\/h2>\n

    C\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t<\/b> theo ph\u01b0\u01a1ng ph\u00e1p n\u00e0y c\u00f3 th\u1ec3 \u0111\u00e1nh li\u00ean t\u1ee5c trong 3 \u2013 4 ng\u00e0y. H\u00f4m sau \u0111\u00e1nh kh\u00f4ng v\u1ec1 th\u00ec ngh\u1ec9 1 ng\u00e0y r\u1ed3i h\u00f4m sau l\u1ea1i \u0111\u00e1nh ti\u1ebfp. C\u00e1ch t\u00ednh l\u00f4 nh\u01b0 sau: Ng\u01b0\u1eddi ch\u01a1i x\u00e1c \u0111\u1ecbnh m\u1ed1c ng\u00e0y b\u1eaft \u0111\u1ea7u; gi\u1ea3 s\u1eed quy \u0111\u1ecbnh ng\u00e0y th\u1ee9 nh\u1ea5t coi \u0111\u1ec1 l\u00e0 AB; ng\u00e0y th\u1ee9 2 \u0111\u1ec1 v\u1ec1 l\u00e0 CD. Ta c\u00f3 A + B = E; C + D = F v\u00e0 bao g\u1ed3m c\u00e1c tr\u01b0\u1eddng h\u1ee3p x\u1ea3y ra sau:<\/span><\/p>\n

      \n
    • Th\u1ee9 nh\u1ea5t, n\u1ebfu E < 10, F < 10 th\u00ec ta l\u1ea5y 10 \u2013 E = X, 10 \u2013 F = Y. Suy ra ng\u00e0y th\u1ee9 3 ta \u0111\u00e1nh l\u00f4 XY.<\/span><\/li>\n
    • Th\u1ee9 hai, t\u00ecnh hu\u1ed1ng E > 10, F < 10 ta ti\u1ebfn h\u00e0nh l\u1ea5y 20 \u2013 E = X, 10 \u2013 F = Y. T\u1eeb \u0111\u00f3 ng\u00e0y th\u1ee9 3 ta \u0111\u00e1nh l\u00f4 XY.<\/span><\/li>\n
    • Th\u1ee9 ba, tr\u01b0\u1eddng h\u1ee3p E > 10, F > 10 l\u1ea5y 20 \u2013 E = X, 20 \u2013 F = Y. T\u01b0\u01a1ng t\u1ef1 nh\u01b0 tr\u00ean \u0111\u00e1nh l\u00f4 ng\u00e0y th\u1ee9 3 l\u00e0 XY.<\/span><\/li>\n
    • Th\u1ee9 t\u01b0, n\u1ebfu E < 10, F > 10 th\u00ec l\u1ea5y 10 \u2013 E = X, 20 \u2013 F = Y. Ta \u0111\u00e1nh YX v\u00e0o ng\u00e0y th\u1ee9 3.<\/span><\/li>\n
    • Th\u1ee9 n\u0103m, n\u1ebfu E = 0 ho\u1eb7c = 10, F = 0 ho\u1eb7c = 10 th\u00ec X, Y l\u00e0 0.<\/span><\/li>\n<\/ul>\n

      B\u1eaft s\u1ed1 l\u00f4 qua s\u1ed1 \u0111\u1ea7u ti\u00ean gi\u1ea3i \u0111\u1eb7c bi\u1ec7t th\u1ee9 2<\/b><\/h2>\n

      \u0110\u00e2y c\u0169ng l\u00e0 m\u1ed9t trong nh\u1eefng <\/span>ph\u01b0\u01a1ng ph\u00e1p b\u1eaft s\u1ed1 l\u00f4 \u0111\u1ec1 chu\u1ea9n <\/span>\u0111\u01b0\u1ee3c c\u00e1c d\u00e2n ch\u01a1i s\u1ed5 x\u1ed1 s\u00e0nh s\u1ecfi \u00e1p d\u1ee5ng ph\u1ed5 bi\u1ebfn. <\/span>C\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t<\/b> n\u00e0y \u0111\u01b0\u1ee3c t\u00ednh nh\u01b0 sau: L\u1ea5y con s\u1ed1 \u0111\u1ea7u c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 trong ng\u00e0y th\u1ee9 2 \u0111\u1ec3 l\u00e0m t\u1ed5ng nu\u00f4i cho c\u1ea3 tu\u1ea7n. Sau \u0111\u00f3 l\u1eadp d\u00e0n l\u00f4 \u0111\u1ec1 c\u1ee7a t\u1ed5ng chu\u1ea9n \u0111\u1ec3 nu\u00f4i; c\u00f3 x\u00e1c su\u1ea5t tr\u00fang t\u01b0\u01a1ng \u0111\u1ed1i cao.<\/span><\/p>\n

      V\u00ed d\u1ee5, th\u1ee9 2 ng\u00e0y 1\/8\/2024  c\u00f3 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t 05488; th\u00ec ch\u00fang ta ti\u1ebfn h\u00e0nh l\u1ea5y con s\u1ed1 \u0111\u1ea7u ti\u00ean l\u00e0 0 l\u00e0m t\u1ed5ng chu\u1ea9n \u0111\u1ec3 nu\u00f4i. \u0110\u1ed3ng th\u1eddi, ch\u00fang ta c\u00f3 d\u00e0n l\u00f4 \u0111\u1ec1 bao g\u1ed3m: 00 \u2013 191\u2013 282 \u2013 373\u2013 464\u2013 55. T\u1eeb \u0111\u00f3, suy ra k\u1ebft qu\u1ea3 c\u1ea7n nu\u00f4i l\u00e0: <\/span><\/p>\n